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Consider the probability that exactly 91

out of 153
registered voters will vote in the presidential election. Assume the probability that a given registered voter will vote in the presidential election is 59%
.

1 Answer

4 votes

Explanation:

We can use the binomial distribution to compute the probability that exactly 91 out of 153 registered voters will vote in the presidential election, assuming that the probability that any given registered voter will vote in the presidential election is 59%.

The probability mass function of the binomial distribution is:

P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)

where:

- n is the number of trials (in this case, the number of registered voters)

- k is the number of successes (in this case, the number of registered voters who will vote in the election)

- p is the probability of success on any individual trial (in this case, the probability that a given registered voter will vote in the election)

Using this formula, we can calculate:

P(exactly 91 out of 153 voters will vote) = (153 choose 91) * 0.59^91 * (1 - 0.59)^(153 - 91)

= 0.037

Therefore, the probability that exactly 91 out of 153 registered voters will vote in the presidential election is approximately 0.037, or about 3.7%.

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