Question

2HCl + Na2SO4 yields 2NaCl + H2SO4

If you start with 20.0 grams of hydrochloric acid, how many grams of sulfuric acid will be produced?

Answer 1

26.9 grams

Step-by-step explanation:

This is a stoichiometry problem. To solve it, we need to determine the number of moles of hydrochloric acid (HCl) that are present in 20.0 grams of the substance. The molar mass of HCl is 36.46 g/mol, so 20.0 grams of HCl is equivalent to 20.0 g / 36.46 g/mol = 0.549 moles of HCl.

According to the balanced chemical equation you provided, two moles of HCl react with one mole of sodium sulfate (Na2SO4) to produce two moles of sodium chloride (NaCl) and one mole of sulfuric acid (H2SO4). This means that for every two moles of HCl that react, one mole of H2SO4 is produced.

Since we have 0.549 moles of HCl, we can expect to produce 0.549 moles / 2 = 0.275 moles of H2SO4.

The molar mass of H2SO4 is 98.08 g/mol, so 0.275 moles of H2SO4 is equivalent to 0.275 mol * 98.08 g/mol = 26.9 grams of sulfuric acid.

Answer 2

26.90 grams of sulfuric acid

Step-by-step explanation:

2HCl + Na2SO4 → 2NaCl + H2SO4

HCl = 36.46 g/mol

H2SO4 = 98.08 g/mol

Calculating 20 grams in HCI

n(HCl) = mass/molar mass

= 20.0 g/36.46 g/mol

= 0.5487 mol

2 moles of HCl produces 1 mole of H2SO4

n(H2SO4) = 0.5487 mol/2

= 0.2744 mol

Mass of H2SO4

mass(H2SO4) = n(H2SO4) x molar mass

= 0.2744 mol x 98.08 g/mol

= 26.90 g