Question

Please help! finding the matrix

Answer 1

Step-by-step explanation:

A =
`\left[\begin{array}{cc}4&-4\\3&-2\end{array}\right]`

3B =
`\left[\begin{array}{cc}12&12\\0&3\end{array}\right]`

4 + 12 = 16 ; 12 + ( - 4) = 8

3 + 0 = 3 ; - 2 + 3 = 1

A + 3B =
`\left[\begin{array}{cc}16&8\\3&1\end{array}\right]`

`(A+3B)^(-1)` =
`\left[\begin{array}{cc}-(1)/(8) &1\\(3)/(8) &-2\end{array}\right]`

X = C ÷ ( A + 3B ) = C ×
`(A+3B)^(-1)`

X =
`\left[\begin{array}{cc}-1&0\\5&2\end{array}\right]` ×
`\left[\begin{array}{cc}-(1)/(8) &1\\(3)/(8) &-2\end{array}\right]` =
`\left[\begin{array}{cc}(1)/(8) &-1\\(1)/(8) &1\end{array}\right]`