Question

___Mg(s) + ___HCl(aq) à ___MgCl2(aq) + ___H2(g)

How many grams of HCl are consumed by the reaction of 5.50 moles of magnesium?

Answer 1

mass of HCl =molar mass of HCl ×moles of HCl

mass of HCl =36.46 g/mol×5 moles

mass of HCl =182.3g

Step-by-step explanation:

for this, u definitely need a periodic table.

Answer 2

401.06 grams of HCl from reaction of 5.50 moles of magnesium

Step-by-step explanation:

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

5.50 moles Mg × 2 moles HCl/1 mole Mg = 11.0 moles HCl

11.0 moles HCl × 36.46 g/mol = 401.06 g HCl