Answer: 2136 molecules of CO2 at STP will occupy a volume of 8.91 × 10^-24 L
Step-by-step explanation:
STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 L of volume. Also, 1 mole of any gas contains 6.022 × 10^23 molecules.
1 mole of CO2 contains = 6.022 × 10^23 molecules
Therefore, 2136 molecules of CO2 will be present in a volume of:
= (1 mole CO2 / 6.022 × 10^23 molecules CO2) × (22.4 L / 1 mole CO2) × (2136 molecules CO2 / 1)
= 8.91 × 10^-24 L