Question

a wire 2.22 m long carries a current of 10.7 a and makes an angle of 40.4° with a uniform magnetic field of magnitude b = 1.99 t. calculate the magnetic force on the wire.

Answer 1

47.86 N

Step-by-step explanation:

The magnetic force on a current-carrying wire in a magnetic field is given by the formula:

F = BIL sinθ

where F is the magnetic force, B is the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

Substituting the given values, we get:

F = (1.99 T) x (10.7 A) x (2.22 m) x sin(40.4°)

F = 47.86 N

Therefore, the magnetic force on the wire is 47.86 N, in the direction perpendicular to both the magnetic field and the wire.

*IG:whis.sama_ent