Explanation:
It can be written as log_4(5x+4)=3
to do this take the log base 4 on both sides
and according to the log rule (log(A)^B) can be written as B×log(A)
we can do the same thing and rewrite
log_4(4)³ as 3×log_4(4) log_4(4) can cancel
out to be one so we are left with 3 × 1 which
is just 3
this will leave 3 to be equal to log_4(5x+4)
to solve this equation for x
4³ = (5x+4)
64= 5x+4
-4 -4
60= 5x
divide both sides by 5
we get
x = 12