Question

What are the values of i and sum after this code sequence isexecutedpublic static void main(String[] args) { int sum = 0;int i = 17;while ( i % 10 !=0){sum += i;i++;}

Answer 1

The code sequence will execute a while loop that increments the value of i and adds it to the sum variable until i is divisible by 10. The initial value of i is 17, and the loop will continue until i becomes divisible by 10.

The values of i and sum after the code sequence is executed will be:

i = 20
sum = 54

Step-by-step explanation:

i starts with the value of 17.
The while loop condition i % 10 != 0 checks if i is not divisible by 10. If i is not divisible by 10, the loop will continue.
Inside the loop, i is added to sum using the statement sum += i;, which is equivalent to sum = sum + i;.
i is then incremented by 1 using i++; statement.
The loop continues until i becomes divisible by 10, which happens when i reaches the value of 20.
At that point, the loop condition i % 10 != 0 becomes false, and the loop exits.
Therefore, the final value of i is 20, and the final value of sum is 54, which is the sum of 17, 18, and 19.