Answer:
7.7 × 10^-10 N
Step-by-step explanation:
To calculate the magnetic force on the airplane, we need to use the formula:
F = qvBsinθ
where:
F = magnetic force
q = net charge
v = velocity of the airplane
B = strength of the magnetic field
θ = angle between the velocity and magnetic field
In this case, the net charge is given as 1540 μc, which we can convert to Coulombs:
q = 1540 μC = 1.54 × 10^-6 C
The velocity of the airplane is given as 100 m/s, and the strength of the Earth's magnetic field is 5.0 × 10^-5 T. However, we also need to know the angle between the velocity and magnetic field. If the airplane is moving perpendicular to the magnetic field, then θ = 90°, which means that sinθ = 1.
Now we can plug in the values and calculate the magnetic force:
F = qvBsinθ
F = (1.54 × 10^-6 C)(100 m/s)(5.0 × 10^-5 T)(1)
F = 7.7 × 10^-10 N
Therefore, the magnetic force on the airplane is 7.7 × 10^-10 N.
*IG:whis.sama_ent