Question

Identify the correct algorithm to append an item in an arrayA.ArrayListAppend(list, newltem) { if (list.allocation Size == list.length) ArrayListResize(list, list.length * 1) list.array[list.size] = newltem list.length = list.length + 2}B.ArrayListAppend(list, newltem) { if (list == list.length) ArrayListResize(list, list.length * 2) list.array[list.length] = newltem list.length = list.length + 3}C.ArrayListAppend(list, newltem) { if (list allocation Size == list.length) ArrayListResize(list, list.length * 2) list.array[list.length] = newltem list.length = list.length + 1}D.ArrayListAppend(list, newltem) { if (list.length == list.lastItem) ArrayListResize(list, list.length * 0) list.array[list.length] = newltem list.length = list.length + 1}

Answer 1

The correct algorithm to append an item in an ArrayList is:

C. ArrayListAppend(list, newltem) {
if (list allocation Size == list.length)
ArrayListResize(list, list.length * 2)
list.array[list.length] = newltem
list.length = list.length + 1
}

Step-by-step explanation:

This algorithm checks if the allocationSize (the capacity of the ArrayList) is equal to the length (the number of elements currently in the ArrayList). If they are equal, it means the ArrayList is full and needs to be resized to accommodate the new item.
If the ArrayList needs to be resized, it resizes it by doubling the length (i.e., list.length * 2) using the ArrayListResize() function (not shown in the provided options).
Then, the new item newltem is added to the ArrayList at the index list.length, which represents the next available position in the ArrayList.
Finally, the length of the ArrayList is incremented by 1 to reflect the addition of the new item.
Options A, B, and D have incorrect logic or inappropriate operations for appending an item to an ArrayList. Option C is the correct algorithm for appending an item to an ArrayList.