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Find the function v(t) that satisfies the following differential equation and initial condition:

10^-2 dv (t)/dt + v(t)=0, v (0)=100V

User T Q
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1 Answer

3 votes

Answer:

We can solve this first-order linear ordinary differential equation using separation of variables.

Starting with the given equation:

10^-2 dv(t)/dt + v(t) = 0

We can rearrange it as:

dv(t)/dt = -10^2 v(t)

Now, separate the variables by dividing both sides by v(t) and dt:

1/v(t) dv(t) = -10^2 dt

Integrate both sides with respect to their respective variables:

∫ 1/v(t) dv(t) = ∫ -10^2 dt

ln|v(t)| = -10^2 t + C

where C is the constant of integration.

Solving for v(t), we exponentiate both sides:

|v(t)| = e^-10^2t * e^C

Using the initial condition v(0) = 100 V, we can determine the value of the constant of integration:

|v(0)| = e^C

100 = e^C

C = ln 100

Therefore, the general solution for v(t) is:

v(t) = ± 100 e^-10^2t

However, since v(0) = 100 V is positive, the solution we want is:

v(t) = 100 e^-10^2t

This is the function that satisfies the given differential equation and initial condition.

User Rudra Prasad Samal
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