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Use the Chain Rule to find dw/dt.w = xey/z, x = t9, y = 2 − t, z = 7 + 8tdw/dt=____

User Anedar
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Answer:

dw/dt = (18t^9 - 9t^10)/(7+8t) - [t^9e^(2-t)/(7+8t)] - (16t^8)(2-t)*e^(2-t)/(7+8t)^2.

Explanation:

To find dw/dt, we can use the chain rule as follows:

dw/dt = (dw/dx)(dx/dt) + (dw/dy)(dy/dt) + (dw/dz)*(dz/dt)

First, let's find the partial derivatives of w with respect to x, y, and z:

dw/dx = ey/z

dw/dy = xe-y/z

dw/dz = -xey/z^2

Next, let's find dx/dt, dy/dt, and dz/dt:

dx/dt = 9

dy/dt = -1

dz/dt = 8t

Now, we can substitute these values into the chain rule formula:

dw/dt = (ey/z)(9) + (xe-y/z)(-1) + (-xey/z^2)*(8t)

Substituting x = t^9, y = 2-t, and z = 7+8t, we get:

dw/dt = [(2-t)t^9/(7+8t)]9 - [t^9e^(2-t)/(7+8t)] + [-t^9(2-t)*e^(2-t)/(7+8t)^2]*8t

Simplifying this expression, we get:

dw/dt = (18t^9 - 9t^10)/(7+8t) - [t^9e^(2-t)/(7+8t)] - (16t^8)(2-t)*e^(2-t)/(7+8t)^2

Therefore, dw/dt = (18t^9 - 9t^10)/(7+8t) - [t^9e^(2-t)/(7+8t)] - (16t^8)(2-t)*e^(2-t)/(7+8t)^2.

User Twhale
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