Final answer:
To find the number of outcomes with at most 25 heads when a fair coin is tossed 27 times, we can use the concept of combinations. By summing the number of outcomes with 0 to 25 heads, we find that there are d) 134,217,349 possible outcomes.
Step-by-step explanation:
When a fair coin is tossed, there are two possible outcomes: heads (H) or tails (T). The number of outcomes in which at most 25 heads occur when the coin is tossed 27 times can be determined using the concept of combinations.
To find the number of outcomes with at most 25 heads, we need to sum the number of outcomes with 0, 1, 2, ..., 25 heads. Using the formula for combinations, this can be calculated as:
C(27, 0) + C(27, 1) + C(27, 2) + ... + C(27, 25).
Using the formula for combinations, which is C(n, r) = n! / (r!(n-r)!), we can calculate the number of outcomes as:
C(27, 0) + C(27, 1) + C(27, 2) + ... + C(27, 25) = 1 + 27 + 351 + ... + 351 = 134,217,349.
Therefore, the correct answer is d) 134,217,349.