Question

in each of the following equations, what hybridization change, if any, occurs for the underlined atom? a. bf3 naf nabf4 b. so2 1/2 o2 so3 c. ethene (ch2=ch2) h2 ch2br-ch2br

Answer 1

In each of the given equations, the hybridization changes for the underlined atoms. In BF3, B changes its hybridization to sp3. In ethene, the carbon atoms change hybridization from sp2 to sp3. In CH2Br-CH2Br, the carbon atoms change hybridization from sp2 to sp3.

Step-by-step explanation:

Answer a:
Boron (B) in BF3 is sp3 hybridized and the hybridization of F is also sp3. The molecular geometry is tetrahedral.

Answer b:
In ethene (CH2=CH2), the carbon atoms are sp2 hybridized. When reacted with H2, one of the sp2 hybrid orbitals on each carbon atom overlaps with an sp3 orbital of a hydrogen atom to form a sigma bond. The other two sp2 hybrid orbitals form sigma bonds between the carbon atoms.

Answer c:
The carbon atoms in CH2Br-CH2Br change hybridization when reacted with H2. The reaction converts the carbon atoms from sp2 hybridization in the double bond of ethene to sp3 hybridization in the single bonds of CH2Br-CH2Br.

Answer 2

The question involves identifying changes in the hybridization of central atoms in chemical reactions. Boron in BF3 changes from sp2 to sp3 when reacting to form NaBF4. Sulfur in SO2 retains sp2 in the formation of SO3, and the carbon atoms in ethene change from sp2 to sp3 in the formation of dibromomethane.

Step-by-step explanation:

The student's question is about the change in hybridization of the underlined atom in each given equation.

1. For BF3 as it reacts to form NaBF4, the boron atom goes from sp2 hybridization to sp3 hybridization.
2. In the oxidation of SO2 to SO3, the sulfur atom retains its sp2 hybridization state as it forms S=O double bonds.
3. During the hydrogenation of ethene (CH2=CH2) to form dibromomethane, the carbon atoms change from sp2 hybridization to sp3 hybridization when the double bond is broken and single bonds to hydrogen and bromine are formed.