To solve this problem, we can use the formula for the equivalent resistance of resistors in parallel and in series.
First, we can find the equivalent resistance of the parallel combination of 15Ω and 60Ω resistors:
1/R_parallel = 1/15Ω + 1/60Ω
1/R_parallel = 4/60Ω + 1/60Ω
1/R_parallel = 5/60Ω
R_parallel = 60Ω/5
R_parallel = 12Ω
Next, we can find the equivalent resistance of the entire circuit:
R_total = R_series + R_parallel
R_total = 18Ω + 12Ω
R_total = 30Ω
Therefore, the best choice for the equivalent resistance of the three-resistor combination is 30Ω.