Answer:
Step-by-step explanation:
Here's one possible implementation of the numEven() function using recursion and a helper function:
cpp
// Helper function to count even elements starting from the given node
size_t countEven(Node* node) const {
if (!node) { // base case: reached end of list
return 0;
} else if (node->data % 2 == 0) { // current node is even
return 1 + countEven(node->next); // count this node and continue to next
} else { // current node is odd
return countEven(node->next); // skip this node and continue to next
}
}
// Recursive function to count even elements in the list
size_t numEven() const {
return countEven(_head);
}
This implementation uses the countEven() helper function to traverse the list recursively, checking each node's data value for evenness and incrementing a counter accordingly. The base case is when the end of the list is reached (i.e., the given node is nullptr). The numEven() function simply calls countEven() starting from the head of the list. If the list is empty or contains no even values, the function will return 0.