Answer:
Explanation:
(i) Let x be the number of hours it takes to travel from Singapore to Hong Kong.
Then, the total time for Option B would be:
Total time for Option B = x + (5x-2/3) hours
Total time for Option A = 3x hours
To find the point at which both options take the same amount of time, we can set the two equations equal to each other and solve for x:
x + (5x-2/3) = 3x
6x - 2/3 = 3x
3x = 2/3
x = 2/9
So, Option B would be faster than Option A if the flight from Singapore to Hong Kong takes less than 2/9 hours (or 13.3 minutes).
(ii) Since James chooses Option B for his outbound flight, we know that the flight from Singapore to Hong Kong takes less than 2/9 hours (or 13.3 minutes).
Let's calculate the total flight time for James' outbound flight using Option B:
Total time for Option B = x + (5x-2/3) hours
Total time for James' outbound flight = x + (5x-2/3) hours
We don't know the actual value of x, but we know that it's less than 2/9 hours. Let's assume that x is 0.2 hours (or 12 minutes):
Total time for James' outbound flight = 0.2 + (5*0.2-2/3) hours
Total time for James' outbound flight = 0.2 + 0.833 hours
Total time for James' outbound flight = 1.033 hours
So, James' total flight time for his outbound flight using Option B would be 1 hour and 2 minutes (since there are 60 minutes in an hour).
Therefore, James' total flight time for his outbound flight using Option B would be 1 hour and 2 minutes.