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A(1) =5/3 a(n) =a(n-1) x-9

User Naho
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2 Answers

4 votes

Answer:

Explanation:

User Roman Kazmin
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6 votes

Explanation:

It looks like you have provided the recursive formula for a sequence, with the initial condition of A(1) = 5/3.

To find the values of the sequence, we can use the recursion formula, which tells us that each term in the sequence is equal to the previous term multiplied by x-9. We can start by finding A(2), which will be:

A(2) = A(1) x (x-9)

A(2) = (5/3) x (x-9)

We can continue this process to find the next terms in the sequence. We can express A(3) in terms of A(2), and then A(4) in terms of A(3), and so on. Here is the general expression for A(n):

A(n) = (5/3) x (x-9)^{n-1}

So, given any value of x, we can use this formula to find the nth term in the sequence.

For example, if x=2, we can find the first few terms of the sequence:

A(1) = 5/3

A(2) = (5/3) x (2-9) = -15

A(3) = (5/3) x (2-9)^2 = 135/4

A(4) = (5/3) x (2-9)^3 = -6075/8

And so on.

User Mike Lambert
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