136k views
1 vote
Suppose you need to pump air into a basketball that is completely deflated. The deflated basketball weighs 0.638 kilograms. After being inflated, the ball weighs 0.643 kilograms. The basketball has a diameter of 0.2 meters. What is the density of air in the ball? Assume the ball is perfectly spherical. Round your answer to two decimal places.

User Pamella
by
7.5k points

1 Answer

3 votes

Answer: the density of air in the ball is 1.19 kg/m^3

Explanation:

V = (4/3)πr^3

where r is the radius of the ball. We know that the diameter of the ball is 0.2 meters, so the radius is 0.1 meters. Substituting this value into the formula, we get:

V = (4/3)π(0.1)^3

= 0.00419 cubic meters

calculate the mass of air in the ball by subtracting the mass of the deflated ball from the mass of the inflated ball:

m_air = m_inflated - m_deflated

= 0.643 kg - 0.638 kg

= 0.005 kg

calculate the density of air in the ball using the formula:

ρ = m_air/V

ρ = 0.005 kg / 0.00419 m^3

= 1.19 kg/m^3

User NickC
by
8.4k points