140k views
2 votes
If you start with 10.0 grams of aluminum hydroxide, how many grams of water will be produced?

User Theron
by
8.0k points

1 Answer

7 votes

Answer: 3.46 grams of water is produced.

Step-by-step explanation:

The chemical formula for aluminum hydroxide is Al(OH)3. When it decomposes, it forms aluminum oxide (Al2O3) and water (H2O).

The balanced chemical equation for this reaction is:

2 Al(OH)3 → Al2O3 + 3 H2O

molar mass of Al(OH)3 = 78.0 g/mol

moles of Al(OH)3 = mass / molar mass = 10.0 g / 78.0 g/mol = 0.1282 mol

mole ratio from the balanced equation to calculate the number of moles of water produced:

moles of H2O = (3/2) * moles of Al(OH)3

moles of H2O = (3/2) * 0.1282 mol = 0.1923 mol

convert the moles of water to grams:

molar mass of H2O = 18.0 g/mol

mass of H2O = moles of H2O * molar mass = 0.1923 mol * 18.0 g/mol = 3.46 g

User Daniel Dimitrov
by
8.4k points