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A boy fired a 40.0g rock with his slingshot. The rock is in contact with the elastic band for 0.5s and its speed as it leaves the weapon is 60.0m/s. Find the average force exerted by the band on the rock

User Bar Gans
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1 Answer

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Answer: 4.8N

Explanation: Using Force (N) = Mass (Kg) * Acceleration (m/s2)
We know the Mass, but its in grams. convert it into kg.
40g / 1000 = 0.04 KG

Then we need to find the acceleration. We can find it by the given values
acceleration = Delta S / Delta T. Or Change in speed / Change in time
So, 60m\s / 0.5s = 120m\s2

now we can use f=ma
X= 0.04 * 120
X= 4.8N

User Magnudae
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