To solve this problem, we can use the ideal gas law:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
Since the volume and the amount of gas are constant in this problem, we can use the following equation to find the relation between the pressure and temperature:
P1/T1 = P2/T2
where P1 and T1 are the initial pressure and temperature, and P2 is the pressure at the unknown temperature T2.
Substituting the given values, we have:
1.82 atm / 293 K = 2.35 atm / T2
Solving for T2, we get:
T2 = 1.82 atm * 293 K / 2.35 atm = 227.37 K
Therefore, the gas in the tire will have a temperature of 227.37 K, or approximately -45.78 degrees Celsius, when the pressure is increased to 2.35 atm.