Answer:
2.09 grams
Step-by-step explanation:
From this equation, for every 4 moles of water produced, we need 1 mole of propane.
The molar mass of water is 18.015 g/mol, and the molar mass of propane is 44.1 g/mol.
First, we need to calculate the number of moles of water produced:
moles of water = mass of water / molar mass of water
moles of water = 3.43 g / 18.015 g/mol
moles of water = 0.1906 mol
From the balanced chemical equation, we know that 4 moles of water are produced for every 1 mole of propane. Therefore, the number of moles of propane required to produce 0.1906 mol of water is:
moles of propane = 0.1906 mol / 4
moles of propane = 0.04765 mol
Finally, we can calculate the mass of propane required:
mass of propane = moles of propane x molar mass of propane
mass of propane = 0.04765 mol x 44.1 g/mol
mass of propane = 2.10 g
Therefore, the mass of propane reacting to produce 3.43 grams of water is 2.10 grams.