Question

Gaseous chlorine is held in two separate containers at identical temperature and pressure. The volume of container 1 is 9.4 L, and it contains 7.2 mol of the gas. The volume of container 2 is 50.1 L. How many moles of the gas are in container 2?

Answer 1

Step-by-step explanation:

According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain the same number of molecules. Therefore, we can set up the following proportion to find the number of moles of chlorine in container 2:

Number of moles in container 1 / volume of container 1 = number of moles in container 2 / volume of container 2

We can plug in the given values:

Number of moles in container 1 = 7.2 mol

Volume of container 1 = 9.4 L

Volume of container 2 = 50.1 L

Number of moles in container 2 = x (unknown)

So we have:

7.2 mol / 9.4 L = x / 50.1 L

To solve for x, we can cross-multiply and simplify:

7.2 mol * 50.1 L = 9.4 L * x

x = (7.2 mol * 50.1 L) / 9.4 L

x = 38.2925 mol

Therefore, there are approximately 38.3 moles of chlorine in container 2.