Question

1. Given: Triangle ABC with vertices A,B,C.

Prove: Triangle ABC is a right triangle.
Find the distances of the sides and use
the Pythagorean Theorem to prove that
it is a right triangle.
c²=a²+b²
PROOF:

Answer 1

A= (-4,7)

B= (-4,-3)

C= (9,-3)

length of AB= 10

length of BC= 13

length of CA= 16.4 (this is the hypotenuse)

so the two shortest sides squared and added together should equal to the longest side squared, according to the equation

10^2+13^2=16.4^2

100+169=269

since this equation is true and follows the Pythagorean Theorem, it proves that this is a right triangle

Explanation: