Answer:
The 95% CI on the proportion of seeds that germinate is (0.89, 0.9256).
Explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Of the 180 seeds that I planted, only 167 germinated.
This means that

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% CI on the proportion of seeds that germinate is (0.89, 0.9256).