Question

The maximum acceleration attained on the interval 0ââ°Â¤tââ°Â¤3 by the particle whose velocity is given by v(t) = t3 -3t2 +12t +4 is

9

12

14

21

40

Answer 1

21

Step-by-step explanation:

v(t) = t³-3t²+12t+4 on the interval 0≤t≤3

has a derivative v'(t) = 3t²-6t+12 ... which is the acceleration of the particle.

To find the maximum acceleration, we want to plug t=3 into our acceleration equation.

v'(3) = a(3) = 3(3)²-6(3)+12 = 21