93.5k views
5 votes
Find the zeroes of y=3x^2-15x-42

User Carolanne
by
7.7k points

1 Answer

3 votes

Answer:

x = - 2 , x = 7

Explanation:

to find the zeros let y = 0 , then

3x² - 15x - 42 = 0 ( divide through by 3 )

x² - 5x - 14 = 0

consider the factors of the constant term (- 14) which sum to give the coefficient of the x- term (- 5)

the factors are + 2 and - 7 , since

2 × - 7 = - 14 and 2 - 7 = - 5 , then

(x + 2)(x - 7) = 0

equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 7 = 0 ⇒ x = 7

User FlexedCookie
by
8.1k points

No related questions found