Answer:
Step-by-step explanation:
To calculate the amount of energy removed from 10.55 kg of water to lower its temperature from 22.5 °C to 3.0 °C, we can use the formula:
Q = m * c * ΔT
where Q is the amount of energy in joules, m is the mass of water in kilograms, c is the specific heat capacity of water (4.184 J/g-K), and ΔT is the change in temperature in degrees Celsius.
First, we need to convert the mass of water from kilograms to grams:
m = 10.55 kg * 1000 g/kg = 10550 g
Next, we need to calculate the change in temperature:
ΔT = 3.0 °C - 22.5 °C = -19.5 °C
Note that we have a negative temperature change because the water is losing heat.
Now, we can plug in the values into the formula:
Q = m * c * ΔT = 10550 g * 4.184 J/g-K * (-19.5 °C) = -820,026 J
The negative sign indicates that energy is being removed from the water, which is consistent with the fact that the temperature is decreasing. Therefore, approximately 820,026 joules of energy are removed from 10.55 kg of water to lower the temperature from 22.5 °C to 3.0 °C.