We have that, in this particular situation, the parametric equations of the projectile are:
x
=
(
v
0
cos
θ
)
t
y
=
h
+
(
v
0
sin
θ
)
t
−
16
t
2
Here,
h
=
0
,since the projectile is launched from ground level. Also,
θ
=
10
∘
and
v
0
=
120
feet/s
. Al last, it can be seen that
16
[feet/s
2
]
t
2
=
g
t
2
2
, where
g
is expressed in feet per squared-second.
With all that, the remaining equations are:
x
=
120
cos
10
∘
t
y
=
120
sin
10
∘
t
−
16
t
2
with the equation for the trajectory:
y
(
x
)
=
(
tan
10
∘
)
x
−
16
x
2
120
2
cos
2
10
∘
Then, plotting the function
y
(
x
)
, we obtain the graph of the projectile's path (Figure 1).
Figure 1: Trajectory of the projectil.