Question

(06.03 MC)

According to the manufacturer, about 26% of sour candy in a package of Sandy's Sours are grape. What is the probability that the first grape candy chosen from the
bag will be, at least, the third candy chosen overall?
00.4524
00.5476
00.1424
O0.8576
00.4052

Answer 1

The probability that the first grape candy chosen is not among the first two is:

P(not grape in first two) = (1 - 0.26) × (1 - 0.26) = 0.5764

Therefore, the probability that the first grape candy chosen will be at least the third candy chosen is:

P(grape candy chosen third or later) = 1 - P(not grape in first two) = 1 - 0.5764 = 0.4236

So, the answer is 0.4236, which is closest to 0.424. Therefore, the correct option is:

0.424