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A 300 mL NaCl solution with a concentration of 3. 0 g/L is mixed with a 500 mL solution containing 7% NaCl (m/v). What is the final concentration of salt in the solution in g/L?

Group of answer choices

61 g/L

1. 1 g/L

30 g/L

45 g/L

User Christien
by
8.5k points

1 Answer

4 votes

Answer:

First, we need to calculate the amount of salt in the 300 mL NaCl solution:

3.0 g/L x 0.3 L = 0.9 g

Next, we need to calculate the amount of salt in the 500 mL 7% NaCl solution:

7 g/100 mL x 0.5 L = 3.5 g

The total amount of salt in the final solution is:

0.9 g + 3.5 g = 4.4 g

The total volume of the final solution is:

300 mL + 500 mL = 800 mL = 0.8 L

Therefore, the final concentration of salt in the solution is:

4.4 g / 0.8 L = 5.5 g/L

The answer is not given among the choices provided.

User Rasa Mohamed
by
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