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Billiard ball A, mass 0. 17 kg, moving due east with a velocity of 4. 0 m/s, strikes stationary billiard ball B, also mass of 0. 17 kg. After the collision, ball A moves off at an angle of 30° north of east with a velocity of 3. 5 m/s, and ball B moves off at an angle of 60 ° south of east. What is the speed of ball B?

User Winklerrr
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Answer: The system that is colliding maintains its momentum. As a result, the ball B's speed is 2m/s (option -a) when it has the same mass as the ball A.

Describe momentum.

A body's capacity to produce the greatest displacement from an applied force is known as momentum. It is the result of adding mass and speed. The two bodies' total initial momentum and total final momentum are equal in a collision.

Consequently, let u be the starting velocity and v be the ending velocity.

m₁ u₁+ m₂ u₂ = m₁ v₁ + m₁ v₂

m₁ = 0.17 kg

u₁ = 4 m/s

m₂ = 0.17 kg

u₂ = 0

v₁ = v₁ cos 30° = 3.5×√3/2

v₂ = v₂cos 60 = v/2

0.68 kg m/s = (0.17 × 3.5×√3/2 ) + (0.17 × v₂/2)

3.5×√3/2/2 + v₂/2 = 4

3.5√3 + v₂ = 8

then v₂ = 8-3.5(1.732)

v₂ = 1.94m/s. = 2m/s

Step-by-step explanation:

User Jessepinho
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