Question

1. 2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O

In the above equation, how many grams of N2 can be made when 14.4 moles of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16

2. For the reaction C + 2H2 → CH4, how many grams of carbon are required to produce 19.5 moles of methane, CH4 ?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element Molar Mass
Hydrogen 1
Carbon 12

3. For the reaction C + 2H2 → CH4, how many moles of carbon are needed to make 119.4 grams of methane, CH4 ?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Carbon

12

4. 2 NH3 + 3 CuO --> 3 Cu + N2 + 3 H2O

In the above equation how many moles of N2 can be made when 127.4 grams of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16

Answer 1

Step-by-step explanation:

First, we need to calculate the number of moles of CuO present in the reaction:

Number of moles = mass / molar mass

Number of moles of CuO = 14.4 mol x (1 mol CuO / 3 mol CuO) = 4.8 mol CuO

Using the stoichiometry of the balanced equation, we know that for every 3 moles of CuO consumed, we can produce 1 mole of N2. Therefore:

Number of moles of N2 = 4.8 mol CuO x (1 mol N2 / 3 mol CuO) = 1.6 mol N2

To calculate the mass of N2 produced, we use the molar mass of nitrogen:

Mass of N2 = number of moles x molar mass = 1.6 mol x 28 g/mol = 44.8 g

Rounding to the nearest tenth, the answer is 44.8 grams of N2 produced.

The balanced equation tells us that one mole of carbon reacts with two moles of hydrogen gas to produce one mole of methane. Therefore, we need to use a ratio to find the amount of carbon needed to produce 19.5 moles of methane:

19.5 mol CH4 x (1 mol C / 1 mol CH4) = 19.5 mol C

To convert moles of carbon to grams, we use the molar mass of carbon:

19.5 mol C x 12 g/mol = 234 g

Rounding to the nearest tenth, the answer is 234.0 grams of carbon needed.

We can start by calculating the number of moles of methane present:

Number of moles = mass / molar mass

Number of moles of CH4 = 119.4 g / 16 g/mol = 7.46 mol

From the balanced equation, we know that one mole of carbon reacts with two moles of hydrogen gas to produce one mole of methane. Therefore:

Number of moles of C = 7.46 mol CH4 x (1 mol C / 1 mol CH4) = 7.46 mol C

Rounding to the nearest tenth, the answer is 7.5 moles of carbon needed.

First, we need to calculate the number of moles of CuO present in the reaction:

Number of moles = mass / molar mass

Number of moles of CuO = 127.4 g / 79.5 g/mol = 1.6 mol CuO

Using the stoichiometry of the balanced equation, we know that for every 3 moles of CuO consumed, we can produce 1 mole of N2. Therefore:

Number of moles of N2 = 1.6 mol CuO x (1 mol N2 / 3 mol CuO) = 0.53 mol N2

Rounding to the nearest tenth, the answer is 0.5 moles of N2 produced.