Answer:
27 child tickets were sold on Thursday.
Explanation:
Let's use algebra to solve the problem.
Let's assume that the number of child tickets sold is "c", and the number of adult tickets sold is "4c" (since four times as many adult tickets as child tickets were sold).
We can write two equations based on the information given in the problem:
The total sales from child tickets: $5.30c
The total sales from adult tickets: $8.80(4c) = $35.20c
The problem tells us that the total sales from both types of tickets was $1093.50:
$5.30c + $35.20c = $1093.50
Combining like terms:
$40.50c = $1093.50
Dividing both sides by 40.50:
c = 27
Therefore, 27 child tickets were sold on Thursday.