Question

suppose the average intensity of the solar radiation that strieks normally on a surface just outside earths atmosphere is 2.1 what would be the radiation pressure exerted on this surface assuming it complete absorbtion

Answer 1

The radiation pressure exerted on the surface would be 6.3 x 10^8 Newtons per square meter, assuming complete absorption.

Step-by-step explanation:

The radiation pressure exerted on a surface can be calculated using the formula:

P = I * c

where P is the radiation pressure, I is the intensity of radiation, and c is the speed of light.

Substituting the given values, we get:

P = 2.1 * c

The value of the speed of light is approximately 3 x 10^8 meters per second.

P = 2.1 * 3 x 10^8

P = 6.3 x 10^8 N/m^2

Therefore, the radiation pressure exerted on the surface would be 6.3 x 10^8 Newtons per square meter, assuming complete absorption.