Question

1. S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O

In the above equation how many grams of water can be made when 4 grams of HNO3 are consumed?

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Sulfur

32

Oxygen

16


2.
Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.



­­2NaClO3­ --> 2NaCl +3O2



How many grams of NaClO3­ were needed to produce 4 grams of O2? Round your answer to the nearest whole number.

Round your answer to the whole number. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Sodium

23

Chlorine

35.5

Copper

63.5

Oxygen

16

Answer 1

1) We can use stoichiometry to determine how many grams of water are produced when 4 grams of HNO3 are consumed.

First, we need to convert the mass of HNO3 to moles. The molar mass of HNO3 is 63 g/mol (1 + 14 + 3x16), so:

4 g HNO3 × 1 mol HNO3 / 63 g HNO3 = 0.0635 mol HNO3

According to the balanced chemical equation, 1 mole of HNO3 produces 2 moles of water. Therefore:

0.0635 mol HNO3 × 2 mol H2O / 6 mol HNO3 = 0.0212 mol H2O

Finally, we can convert the moles of water to grams using the molar mass of water, which is 18 g/mol:

0.0212 mol H2O × 18 g H2O / 1 mol H2O = 0.3816 g H2O

Therefore, when 4 grams of HNO3 are consumed, approximately 0.3816 grams of water can be produced.

2)To determine the amount of NaClO3 needed to produce 4 grams of O2, we need to use stoichiometry.

According to the balanced equation, 2 moles of NaClO3 produces 3 moles of O2. Therefore:

3 mol O2 / 2 mol NaClO3 = 48 g O2 / x g NaClO3

where x is the mass of NaClO3 needed to produce 4 grams of O2.

Solving for x, we get:

x = 32 g NaClO3

Therefore, approximately 32 grams of NaClO3 are needed to produce 4 grams of O2. Rounded to the nearest whole number, the answer is 32.