Answer:
a = 0.5555 m/s²
Explanation:
First, we need to convert the velocities from km/h to m/s.
20 km/h = 20 * 1000 m/3600 s
= 20000/3600 m/s
≈ 5.56 m/s
60 km/h = 60 * 1000 m/3600 s
= 60000/3600 m/s
= 16.67 m/s
We can use the formula for uniform acceleration:
a = (vf - vi) / t
where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time taken.
Plugging in the values we have:
a = (16.67 m/s - 5.56 m/s) / 20 s
a = 11.11 m/s / 20 s
a = 0.5555 m/s²
Therefore, the acceleration of the train is 0.5555 m/s².