Question

Caleb runs a farm stand that sells strawberries and grapes. Yesterday Caleb sold 28 pounds of strawberries and 37 pounds of grapes for a total revenue of $183.50. Today

he sold 14 pounds of strawberries and 16 pounds of grapes for a total revenue of $85.50. Determine the price of each pound of strawberries and the price of each pound of grapes.

Answer 1

Let's represent the price of a pound of strawberries as "s" and the price of a pound of grapes as "g".

From the given information, we can create two equations:

Equation 1: 28s + 37g = 183.5

Equation 2: 14s + 16g = 85.5

We can use the method of elimination to solve for s and g. First, we'll multiply Equation 2 by 2 to make the coefficients of s in both equations equal:

28s + 32g = 171

Now we'll subtract Equation 1 from this equation to eliminate g:

28s + 32g - (28s + 37g) = 171 - 183.5

Simplifying:

-5g = -12.5

g = 2.5

Now that we know the price of a pound of grapes is $2.5, we can substitute that value back into either Equation 1 or Equation 2 to solve for s. Let's use Equation 1:

28s + 37(2.5) = 183.5

Simplifying:

28s + 92.5 = 183.5

28s = 91

s = 3.25

Therefore, the price of each pound of strawberries is $3.25 and the price of each pound of grapes is $2.50.