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The area of a rectangle is given by 3x³ - 9x² -12x. If the length of the rectangle is given by

2x³ 18x² + 40x, find the WIDTH of the rectangle. Show ALL your work.

The area of a rectangle is given by 3x³ - 9x² -12x. If the length of the rectangle-example-1

1 Answer

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Answer:

w = (3x - 6)(x + 2) / 2(x + 5)(x + 4)

Explanation:

To find the width of the rectangle, we need to use the formula for the area of a rectangle:

Area = length x width

We are given that the area of the rectangle is:

3x³ - 9x² - 12x

And the length of the rectangle is:

2x³ + 18x² + 40x

So we can substitute these values into the formula to get:

3x³ - 9x² - 12x = (2x³ + 18x² + 40x) x width

Expanding the right side of the equation, we get:

3x³ - 9x² - 12x = 2x³ x width + 18x² x width + 40x x width

Simplifying the terms on the right side, we get:

3x³ - 9x² - 12x = (2x³ + 18x² + 40x)w

Dividing both sides by (2x³ + 18x² + 40x), we get:

w = (3x³ - 9x² - 12x) / (2x³ + 18x² + 40x)

Factoring out x from the terms in the numerator and denominator, we get:

w = x(3x² - 9x - 12) / 2x(x² + 9x + 20)

Simplifying the expression, we get:

w = (3x² - 9x - 12) / 2(x² + 9x + 20)

Now, we can factor the numerator and denominator to get:

w = (3x - 6)(x + 2) / 2(x + 5)(x + 4)

Therefore, the width of the rectangle is:

w = (3x - 6)(x + 2) / 2(x + 5)(x + 4)
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