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What is the temperature inside a 36.81 L balloon that is holding 2.845 moles of gas at 5.213 atm?

R=0.08206 L⋅atm/mol⋅K

a. 548.8 °C

b. 244.8 °C

c. 821.9 °C

d. 278.1°C

2 Answers

2 votes

Answer:

OPTION C

Step-by-step explanation:

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User Pramendra Gupta
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We can use the ideal gas law to solve for the temperature:

PV = nRT

where:

P = pressure = 5.213 atm

V = volume = 36.81 L

n = moles = 2.845 mol

R = gas constant = 0.08206 L·atm/mol·K

Solving for T:

T = PV/nR

T = (5.213 atm * 36.81 L) / (2.845 mol * 0.08206 L·atm/mol·K)

T = 548.8 K

Converting from Kelvin to Celsius:

T = 548.8 K - 273.15

T = 275.65°C

Therefore, the temperature inside the balloon is approximately 275.65°C, which is closest to option (d) 278.1°C.

User Mokshino
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8.0k points