Question

Experts!! Thanks for stopping by my question! I would really appreciate the help! I've attached the question below. Thanks!

I'd appreciate if you made sure to double check your answers and provide everything the question is asking! INCLUDE ALL STEPS!

Answer 1

put 0 where the x is in the equation

f(x) = y

f(x) = (x-2)²

y = (0-2)²

y = 4

does the graph go thru (0,4) ?

no

so this is not the graph

Answer 2

the vertical asymptote is in the wrong place

Explanation:

You want a simple explanation why the graph shown is not a graph of 1/f(x) = 1/(x -2)².

Asymptote

The zero of f(x) is at x = 2. This will be the equation of the vertical asymptote of the reciprocal function.

The given graph has a vertical asymptote at x = -2, so cannot be a graph of 1/f(x).