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Zero(s) where the graph crosses the -axis for f(x)=(x+3)(x+2)(x-1)

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Answer:

Explanation:

Graph crosses x-axis when y=0 (that is f(x)=0).


(x+3)(x+2)(x-1)=0 \text{ when:}


x+3=0\text{ or }x+2=0\text{ or }x-1=0


\text{So }x=-3,-2,1

SOLUTION: Graph crosses x-axis at
x=-3,-2,1.

User TheMrbikus
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