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Rosetta averages 148 points per bowling game with a standard deviation of 14 points. Suppose Rosetta's points per bowling game are normally distributed. Let X= the number of points per bowling game. Then X∼N(148,14).

If necessary, round to three decimal places.
Provide your answer below:
Suppose Rosetta scores 110 points in the game on Thursday. The z-score when x=110 is . The mean is .
This z-score tells you that x=110 is standard deviations to the left of the mean.

User Shaul Behr
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1 Answer

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29 votes

given

average = 148

standard deviation = 14

let Z score when x is 110

z score = 110-148/ 14 = -2.714

suppose Rosseta scores 110 points in the game on Thursday,

the Z score when X is 110 is -2.174

the mean is 148.

The Z scores tell you that X = 110 is 2.714

standard deviation to the left of the mean.

User Lewis Cirne
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