Question

13. The rate constant for a certain first-order reaction is 0.40/min. What is the initial rate in mole/Llmin, if the initial concentration of the compound involved is 0.50 mol/L?

a. 20
b. 30
c. 45
d. 55

Answer 1

The initial rate in mole/Llmin, if the initial concentration of the compound involved is 0.50 mol/L is 0.20 mol/L/min.

Using the rate law for a first-order reaction is given by the equation:

Rate = k * {Reactant}

In this case, the rate constant k is given as 0.40/min, and the initial concentration Reactant is 0.50 mol/L.

Rate =
`0.40 \, \text{min}^(-1) * 0.50 \, \text{mol/L}`

Now, calculate the initial rate:

Rate =
`0.20 \, \text{mol/L/min}`

So, the correct answer is option (a) 20. The initial rate is 0.20 mol/L/min.