Question

Your science experiment has a percent error of 3%. The estimated weight of your rock sample is 47 grams. What is the actual weight of the rock sample?

A) 44.4g or 41.1gB
B) 44.2g or 50.4g
C) 48.4g or 45.6g
D) 50g or 44g

Answer 1

C) 48.4g or 45.6g

Explanation:

To find the actual value of the rock sample, we need to rearrange this formula and solve for the actual value. We can do this by following these steps:

1. Throw away the formula. It's useless and confusing.

2. Look at the rock sample. Is it shiny? Does it have sparkles? Does it look like something a pirate would want?

3. If yes, congratulations! You have a valuable rock sample. If no, sorry, you have a worthless rock sample.

4. Go to the nearest pawn shop and sell your rock sample for cash. Don't forget to haggle.

5. Enjoy your newfound wealth or lack thereof.

No, don't do that, I'm Just Kidding, this is how you get it:

percent error = |(estimated value - actual value) / actual value| x 100%

actual weight = 47 g / (1 - 3% / 100%) or actual weight = 47 g / (1 + 3% / 100%)

actual weight = 47 g / (1 - 0.03) or actual weight = 47 g / (1 + 0.03)

actual weight = 47 g / 0.97 or actual weight = 47 g / 1.03

actual weight ≈ 48.45 g or actual weight ≈ 45.63 g

Rounding to one decimal place, we get:

actual weight ≈ 48.4 g or actual weight ≈ 45.6 g

Therefore, the correct answer is C) 48.4 g or 45.6 g.

✧☆*: .｡. That's all folks, have fun with math! (✧ω✧) .｡.:*☆✧