Answer:
9366.784 joules (J)
Step-by-step explanation:
To calculate the amount of energy released when 43 grams of water cools from 70°C to 18°C, we need to use the specific heat capacity of water, which is 4.184 J/g·°C. The formula we use is:
Q = m * c * ΔT
-Q is the amount of heat energy released
-m is the mass of the substance
-c is the specific heat capacity of the substance, and ΔT is the change in temperature.
Substituting the given values into the formula, we get:
Q = 43 g * 4.184 J/g·°C * (70°C - 18°C)
Q = 43 g * 4.184 J/g·°C * 52°C
Q = 9366.784 JTherefore, the amount of energy released when 43 grams of water cools from 70°C to 18°C is 9366.784 joules (J).