Answer:
Step-by-step explanation:
To calculate the amount of energy required to heat 147 grams of iron from 30°C to 51°C, we need to use the specific heat capacity of iron, which is 0.45 J/g·°C.
The formula we use is:
Q = m * c * ΔT
where Q is the amount of heat energy required, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
Substituting the given values into the formula, we get:
Q = 147 g * 0.45 J/g·°C * (51°C - 30°C)
Q = 147 g * 0.45 J/g·°C * 21°C
Q = 139.23 J
Therefore, the amount of energy required to heat 147 grams of iron from 30°C to 51°C is 139.23 joules (J).