Question

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Question 4 (Worth 4 points)
(07.02 MC)

Rewrite 9x2 + 3xy + 15x + 5y in factored form.

(3x + 3)(5x + y)

(3x + 5)(3x + y)

(3x + 5y)(3x + 1)

(3x + y)(5x + 3)
Already picked D and its wrong

Answer 1

b) (3x + 5)(3x + y)

Explanation:

First, we can factor out a common factor of 3x from the first two terms:

9x^2 + 3xy = 3x(3x + y)

Now, we can factor out a common factor of 5 from the last two terms:

15x + 5y = 5(3x + y)

Putting it all together, we get:

9x^2 + 3xy + 15x + 5y = 3x(3x + y) + 5(3x + y) = (3x + 5)(3x + y)