Question

A man married 7 wives in his

house each of them gave birth to
7 children but 3 women died how
many of them are in the house

Answer 1

Answer: 56 and or 53

Step-by-step explanation:

since they all gave birth to 7 children, 7x7.

7x7 = 49

there are 7 wives.

49+7=56

3 died.

56-53=53

OR

3 died BUT they did not leave the house.

56