20.2k views
1 vote
A man married 7 wives in his

house each of them gave birth to
7 children but 3 women died how
many of them are in the house

User Nlinscott
by
8.1k points

1 Answer

3 votes

Answer: 56 and or 53

Step-by-step explanation:

since they all gave birth to 7 children, 7x7.

7x7 = 49

there are 7 wives.

49+7=56

3 died.

56-53=53

OR

3 died BUT they did not leave the house.

56

User Boeboe
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.